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Post by RuthlessDragon6 on Jan 6, 2021 6:17:10 GMT -8
Well if you know tables well its easy peasy, I can explain you in seconds... Schools tend to always teach you the hard methods... 😂 Ah... It's embarrassing but I only know tables till 15... And of 19 and 20... 16, 17, and 18, well can't learn them... Well explain if ya can...
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Post by Dark on Jan 6, 2021 6:19:49 GMT -8
Ah... It's embarrassing but I only know tables till 15... And of 19 and 20... 16, 17, and 18, well can't learn them... Well explain if ya can... lol give a question, its been a while but I can definitely try...
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Post by Dark on Jan 6, 2021 6:20:47 GMT -8
Well if you know tables well its easy peasy, I can explain you in seconds... Schools tend to always teach you the hard methods... 😂 Ah... It's embarrassing but I only know tables till 15... And of 19 and 20... 16, 17, and 18, well can't learn them... tbh for R&P if you only table till 9, it's enough...
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Post by RuthlessDragon6 on Jan 6, 2021 6:24:34 GMT -8
Q.no 24...
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Post by RuthlessDragon6 on Jan 6, 2021 6:25:46 GMT -8
Q.no 24... Before you ask, yes, it's RS Aggrawal....
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Post by Dark on Jan 6, 2021 6:27:17 GMT -8
Q.no 24... This is equations anyways I'll try to solve it if ya want...
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Post by RuthlessDragon6 on Jan 6, 2021 6:27:22 GMT -8
Ah... It's embarrassing but I only know tables till 15... And of 19 and 20... 16, 17, and 18, well can't learn them... tbh for R&P if you only table till 9, it's enough... R&P???
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Post by RuthlessDragon6 on Jan 6, 2021 6:28:38 GMT -8
Q.no 24... This is equations anyways I'll try to solve it if ya want... Then what we're ya talking about, and yeah, if ya can plz explain that one, I was lucky enough that it didn't came in this exam, but I'm sure it'll come in finals...
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Post by Dark on Jan 6, 2021 6:50:33 GMT -8
RuthlessDragon6 Let the breadth of rectangle be 'l' Acc. to given conditionlength = l+7 It can be said that the length of the wire is equal to the perimeter of the rectangle formed Therefore Perimeter = 86 cm Now, Perimeter of rectangle = 2(b+l) 86 = 2(l+l+7) 86/2 = 2l + 7 43-7 = 2l 36 = 2l l = 36/2 1 = 18 breadth of rectangle = 18 cm length of rectangle = l+7 = 18+7 = 25 cm
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Post by Dark on Jan 6, 2021 6:54:21 GMT -8
Q.no 24... Before you ask, yes, it's RS Aggrawal.... doesn't matter Maths is Maths, which ever book it maybe... 😂
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Post by Dark on Jan 6, 2021 6:56:55 GMT -8
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Post by RuthlessDragon6 on Jan 6, 2021 7:06:06 GMT -8
RuthlessDragon6 Let the breadth of rectangle be 'l' Acc. to given conditionlength = l+7 It can be said that the length of the wire is equal to the perimeter of the rectangle formed Therefore Perimeter = 86 cm Now, Perimeter of rectangle = 2(b+l) 86 = 2(l+l+7) 86/2 = 2l + 7 43-7 = 2l 36 = 2l l = 36/2 1 = 18 breadth of rectangle = 18 cm length of rectangle = l+7 = 18+7 = 25 cm Ok... After solving the while process on my one after reading this, I can say that it's clear now, thanks bro, now well I'm going to practice all the questions...
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Post by RuthlessDragon6 on Jan 6, 2021 7:06:47 GMT -8
Before you ask, yes, it's RS Aggrawal.... doesn't matter Maths is Maths, which ever book it maybe... 😂 And I think nearly all books contain the same thing... CBSE...
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Post by RuthlessDragon6 on Jan 6, 2021 7:07:02 GMT -8
Checked it, thanks again bro...
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Post by Dark on Jan 6, 2021 7:12:42 GMT -8
Welcome 😀
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